Nội dung bài giảng
60. Tìm x, biết:
a) \(x - \frac{3}{4}=\frac{1}{2}\) ;
b) \(\frac{-5}{6}-x=\frac{7}{12}+\frac{-1}{3}\) ;
Hướng dẫn giải.
a) \(x= \frac{1}{2}+\frac{3}{4}=\frac{5}{4}\) ;
b) \(\frac{-5}{6}-x=\frac{7}{12}+\frac{-1}{3}\)
\(\frac{-5}{6}-x=\frac{7-4}{12}\)
\(\frac{-5}{6}-x=\frac{3}{12}\).
\(x=\frac{-5}{6}-\frac{3}{12}\)
\(x=\frac{(-10)+(-3)}{12}=\frac{-13}{12}.\)