Hạt nhân \(_{10}^{20}Ne\) có khối lượng \({m_{Ne}} = 19,986950u\). Cho biết \({m_p} = 1,00726u;{m_n} = 1,008665u;\)  \(1u = 931,5MeV/{c^2}\). Năng lượng liên kết riêng của \(_{10}^{20}Ne\) có giá trị là bao nhiêu? 

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