A.A.
\(\left[ \begin{array}{l}
x = \frac{\pi }{{50}} + \frac{{k2\pi }}{5}\\
x = \frac{{17\pi }}{{90}} + \frac{{k\pi }}{9}
\end{array} \right.\;\left( {k \in Z} \right)\)
B.B.
\(\left[ \begin{array}{l}
x = - \frac{{3\pi }}{{50}} + \frac{{k2\pi }}{5}\\
x = \frac{{17\pi }}{{30}} + \frac{{k\pi }}{9}
\end{array} \right.\;\left( {k \in Z} \right)\)
C.C.
\(\left[ \begin{array}{l}
x = \frac{\pi }{{50}} + \frac{{k2\pi }}{5}\\
x = \frac{\pi }{{30}} + \frac{{k2\pi }}{9}
\end{array} \right.\;\left( {k \in Z} \right)\)
D.D.
\(\left[ \begin{array}{l}
x = \frac{{3\pi }}{{50}} + \frac{{k2\pi }}{5}\\
x = \frac{{17\pi }}{{90}} + \frac{{k2\pi }}{9}
\end{array} \right.\;\left( {k \in Z} \right)\)
