Rút gọn: \(A = \sqrt {16x + 16} - \sqrt {9\left( {x + 1} \right)} \)\(\,+ \sqrt {25x + 25} \,\,\,\,\left( {x \ge - 1} \right)\)
Ta có:
\(A = \sqrt {16x + 16} - \sqrt {9\left( {x + 1} \right)} \)\(\,+ \sqrt {25x + 25}\)
\(\begin{array}{l}
= \sqrt {16\left( {x + 1} \right)} - \sqrt {9\left( {x + 1} \right)} + \sqrt {25\left( {x + 1} \right)} \\
= \sqrt {{4^2}\left( {x + 1} \right)} - \sqrt {{3^2}\left( {x + 1} \right)} + \sqrt {{5^2}\left( {x + 1} \right)}
\end{array}\)
\( = 4\sqrt {x + 1} - 3\sqrt {x + 1} + 5\sqrt {x + 1} \)\(\,= 6\sqrt {x + 1} \)